Guides/Mining/Sand Mining - Revision history

Qu at 09:27, 12 April 2011

2011-04-12T09:27:31Z

Zerrenor: /* Four Colors (Three Pairs) */ Proposed replacement step 7 is identical to step 15, and therefore factually impossble. Original configuration verified correct.

2010-12-02T06:23:08Z

Four Colors (Three Pairs): Proposed replacement step 7 is identical to step 15, and therefore factually impossble. Original configuration verified correct.

Cegaiel: /* Four Colors (Three Pairs) */

2010-11-14T06:54:08Z

Four Colors (Three Pairs)

Cegaiel: /* Four Colors (Three Pairs) */

2010-11-14T06:52:47Z

Four Colors (Three Pairs)

Cegaiel: /* Four Colors (Three Pairs) - Replacement Proposal */

2010-11-14T06:52:06Z

Four Colors (Three Pairs) - Replacement Proposal

Cegaiel: /* Four Colors (Three Pairs) - Replacement Proposal */

2010-11-14T06:47:27Z

Four Colors (Three Pairs) - Replacement Proposal

Cegaiel at 06:01, 13 November 2010

2010-11-13T06:01:36Z

Cegaiel: /* Four Colors (Three Pairs) */

2010-11-13T06:00:52Z

Four Colors (Three Pairs)

Cegaiel at 05:59, 13 November 2010

2010-11-13T05:59:38Z

Cegaiel: /* Four Colors (Three Pairs) */

2010-11-13T05:56:45Z

Four Colors (Three Pairs)

← Older revision		Revision as of 09:27, 12 April 2011
Line 308:		Line 308:
	# A-1, A-2, A-3, A-4, A-5 ''Breaks A-1, A-2, A-3, A-4, A-5''		# A-1, A-2, A-3, A-4, A-5 ''Breaks A-1, A-2, A-3, A-4, A-5''
	\|}		\|}
		+
		+	== Three Colors (Two Triple) ==
		+
		+	It's possible to break one stone.

@@ Line 195: / Line 195: @@
 # A-2, B-2, C-1  ''This will break all 3 stones''
 # A-1, B-1, C-2, D  ''This will break all 4 stones''
 |}

@@ Line 195: / Line 195: @@
 # A-2, B-2, C-1  ''This will break all 3 stones''
 # A-1, B-1, C-2, D  ''This will break all 4 stones''
-# ? See below (<b>Replacement Proposal</b>). If you have 3 stones remaining, then click the last 3 to break all.
+# <b><font color=red>?</font></b> See below (<b>Replacement Proposal</b>). If you have 3 stones remaining, then click the last 3 to break all.
 |}

@@ Line 195: / Line 195: @@
 # A-2, B-2, C-1  ''This will break all 3 stones''
 # A-1, B-1, C-2, D  ''This will break all 4 stones''
-# ? See below (Replacement Proposal). If you have 3 stones remaining, then click the last 3 to break all.
+# ? See below (<b>Replacement Proposal</b>). If you have 3 stones remaining, then click the last 3 to break all.
 |}

← Older revision		Revision as of 06:52, 14 November 2010
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	=== Four Colors (Three Pairs) - Replacement Proposal ===		=== Four Colors (Three Pairs) - Replacement Proposal ===
−	The above pattern does not work for me. The 14 sets always leaves 3 stones remaining. Working the remaining 3 stones (a 15th set), will break the last 3 stones. I propose below be the new standard for 4 color (3 Pair). But leaving original alone, above, in case someone wants to verify or can see something I am missing. ~[http://www.atitd.org/wiki/tale4/User:Cegaiel/Macros/SandMining Cegaiel]	+	The above pattern does not work for me. The 14 sets always leaves 3 stones remaining. Working the remaining 3 stones (a 15th set), will break the last 3 stones. I propose below be the new standard for 4 color (3 Pair). But leaving original alone, above, in case someone wants to verify or can see something I am missing. The only difference of above and this pattern, is the addition of set 15 (which also changes the ''comments'')   ~[http://www.atitd.org/wiki/tale4/User:Cegaiel/Macros/SandMining Cegaiel]

@@ Line 201: / Line 201: @@
 === Four Colors (Three Pairs) - Replacement Proposal ===
-The above pattern does not work for me. The 14 sets always leaves 3 stones remaining. Working the remaining 3 stones (a 15th set), will break the last 3 stones. I propose below be the new standard for 4 color (3 Pair). But leaving original alone, above, in case someone wants to verify or can see something I am missing. ~[[User:Cegaiel | Cegaiel]]
+The above pattern does not work for me. The 14 sets always leaves 3 stones remaining. Working the remaining 3 stones (a 15th set), will break the last 3 stones. I propose below be the new standard for 4 color (3 Pair). But leaving original alone, above, in case someone wants to verify or can see something I am missing. ~[http://www.atitd.org/wiki/tale4/User:Cegaiel/Macros/SandMining Cegaiel]
@@ Line 223: / Line 223: @@
 # A-1, B-2, C-2  ''This will break remaining 3 stones''
 |}
 == Four Colors (Triple and Pair) ==

@@ Line 27: / Line 27: @@
 # A, B, C, D, E, F, G  ''Breaks all 7 stones''
 |}
 == Six Colors (One Pair) ==
@@ Line 53: / Line 55: @@
 # A-2, C, D, F  ''This workload will crumble the remaining stones''
 |}
 === Six Colors (Alternate) ===
@@ Line 77: / Line 81: @@
 # A-2, B, C, D, E, F ''Breaks the remaining 6''
 |}
 == Five Colors (Two Pairs) ==
@@ Line 103: / Line 109: @@
 # A-2, B-2, C, D, E ''Breaks the remaining 5 stones''
 |}
 === Five Colors - Alternate Method ===
@@ Line 130: / Line 137: @@
 The same process can be applied to 6- and 7-color fields. Make 6 sets of complementary pairs of workloads, and then one big one to break them all.
 == Five Colors - (Triple) ==
@@ Line 160: / Line 169: @@
 # A-3, B, C, D, E  ''Breaks B, C, D, and E''
 |}
 == Four Colors (Three Pairs) ==
@@ Line 185: / Line 196: @@
 # A-1, B-1, C-2, D  ''This will break all 4 stones''
 |}
 === Four Colors (Three Pairs) - Replacement Proposal ===
@@ Line 209: / Line 222: @@
 # A-1, B-2, C-2  ''This will break remaining 3 stones''
 |}
 == Four Colors (Triple and Pair) ==
@@ Line 234: / Line 250: @@
 |}
 == Four Colors (Quadruple) ==
@@ Line 260: / Line 278: @@
 # A-1, A-2, A-3, A-4 ''Breaks A-1, A-2, A-3''
 |}
 == Three Colors (Triple and Two Pairs) ==
@@ Line 272: / Line 292: @@
 None.
 |}
 == Three Colors (Quadruple and Pair) ==
@@ Line 291: / Line 313: @@
 |}
 == Three Colors (Quintuple) ==

← Older revision		Revision as of 05:56, 13 November 2010
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	=== Four Colors (Three Pairs) - Replacement Proposal ===		=== Four Colors (Three Pairs) - Replacement Proposal ===
−	The above pattern does not work for me. The 14 sets always leaves 3 stones remaining. Working the remaining 3 stones (a 15th set), will break the last 3 stones. I propose below be the new standard for 4 color (3 Pair). But leaving original alone in case someone wants to verify or can see something I am missing. ~[[User:Cegaiel \| Cegaiel]]	+	The above pattern does not work for me. The 14 sets always leaves 3 stones remaining. Working the remaining 3 stones (a 15th set), will break the last 3 stones. I propose below be the new standard for 4 color (3 Pair). But leaving original alone, above, in case someone wants to verify or can see something I am missing. ~[[User:Cegaiel \| Cegaiel]]