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Difference between revisions of "Talk:Firepit"

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(→‎Possible yield formulae: Leeks, unexpected result..)
(→‎Possible yield formulae: another leeks update)
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   lime = int( t^(1/3) * int(limestone/16) )
 
   lime = int( t^(1/3) * int(limestone/16) )
 
   ash = int( t^(1/3) * int(flax/20) )
 
   ash = int( t^(1/3) * int(flax/20) )
   ash = int( t^(1/3) * int(leeks/50) )
+
   ash = int( t^(1/3) * int(leeks/40) )    (Not 50! See below)
 
   ash = int( t^(1/2) * int(papy/20) )
 
   ash = int( t^(1/2) * int(papy/20) )
  
The way to test this would be to try each of these combinations, if anyone wants to have a go:
+
Testing results:
  
 
   200 wood + 15 limestone + 19 flax, no stoking -> 25 cc, NO ash, NO lime
 
   200 wood + 15 limestone + 19 flax, no stoking -> 25 cc, NO ash, NO lime
 
   200 wood + 16 limestone + 20 flax, no stoking -> 24 cc, 2 ash, 2 lime
 
   200 wood + 16 limestone + 20 flax, no stoking -> 24 cc, 2 ash, 2 lime
 
   200 wood + 49 leeks, no stoking -> 24 cc, 2 ash. (Hmmm)
 
   200 wood + 49 leeks, no stoking -> 24 cc, 2 ash. (Hmmm)
   200 wood + 39 leeks, no stoking -> ??
+
   200 wood + 39 leeks, no stoking -> 25 cc, NO ash
 
   200 wood + 19 papy, no stoking -> 25 cc, NO ash
 
   200 wood + 19 papy, no stoking -> 25 cc, NO ash
 
   200 wood + 20 papy, no stoking -> 25 cc, 3 ash
 
   200 wood + 20 papy, no stoking -> 25 cc, 3 ash
  
 
--[[User:Inkoaten|Inkoaten]] 19:33, 9 March 2009 (EST)
 
--[[User:Inkoaten|Inkoaten]] 19:33, 9 March 2009 (EST)

Revision as of 03:34, 14 March 2009

Can someone add pictures of the orange - yellow - white stages, and make it a bit clearer when to stoke the fire? It's tough to do with just this info. -shadeking

  • I added information on the color of a fire as well. The Hue of a fire will be 0 during the stoke phase and 60 during the no stoke phase. --Vulpine 18:08, 26 January 2009 (EST)


Data

stokes limestone dried flax leeks dried papyrus -> lime ash charcoal
0 100 100 100 100 13 32 25
0 100 - - - 13 0 25
0 - - 100 - 0 4 25
1 100 100 100 - 13 4 25
15 100 100 100 100 19 51 35
25 100 100 - - 21 18 39
25? 100 100 100 100 22 60 40
30 100 100 - - 22 19 42
30? 100 100 100 100 22 61 41
50 100 100 100 100 26 76 48

Not sure if anyone's collecting stoke data (appears similar to T3). Here's a data point to start with:

200 limestone; 100 dried flax; 200 wood @ 25 stokes (~18 mins) = 21 Lime, 18 Ash, 39 cc

100 limestone; 100 dried flax; 100 leeks; 200 wood @ 1 stoke = 13 lime, 4 ash, 25 cc


Here's my T4 data:

100 limestone; 100 dried flax; 100 dried papyrus; 100 leeks; 200 wood @ 15 stokes = 19 lime, 51 ash, 35 cc

McArine data(not sure about the 30 stoke one being 30 stokes):

  • 100 limestone; 100 dried flax; 100 dried papyrus; 100 leeks; 200 wood @ 0 stokes = 13 lime, 32 ash, 25 cc
  • 100 limestone; 100 dried flax; 100 dried papyrus; 100 leeks; 200 wood @ 25 stokes = 22 lime, 60 ash, 40 cc
  • 100 limestone; 100 dried flax; 100 dried papyrus; 100 leeks; 200 wood @ 30 stokes = 22 lime, 61 ash, 41 cc
  • 100 limestone; 100 dried flax; 100 dried papyrus; 100 leeks; 200 wood @ 50 stokes = 26 lime, 76 ash, 48 cc

More: 100 limestone, 0 stokes -> 13 lime 100 leeks, 0 stokes -> 4 ash

I moved the following data here from the main page so it's all in one place: --Inkoaten 17:19, 9 March 2009 (EST)

Stokes Lime Ash
20 21 52
30 23 n/a
36 26 n/a
40 n/a 72
60 27 n/a
65 n/a 83

--mosen 18:37, 19 January 2009 (EST)

tehmoosh Firetests
Limestone/Papy Limestone/Papy/Leeks
Minutes of
Stoking
Lime Ash Lime Ash
50 27 50 27 58
60 29 54 29 63

Firepit was stoked for the time listed and then allowed to die out. This results in about 5 minutes of additional burn time as the fire dies.

Akmenotep Fire Tests

100 Leeks, 100 Dried Flax

  • 40 Stokes - 28 Ash, 44 Charcoal


100 Leeks, 100 Dried Flax, 100 Papyrus

  • 40 Stokes - 70 Ash, 45 Charcoal


100 Limestone, 100 Leeks, 100 Dried Flax

  • 9 Stokes - 21 Ash, 18 Lime, 33 Charcoal
  • 19 Stokes - 23 Ash, 20 Lime, 37 Charcoal
  • 33 Stokes - 26 Ash, 23 Lime, 42 Charcoal
  • 36 Stokes - 28 Ash, 24 Lime, 45 Charcoal
  • 40 Stokes - 28 Ash, 24 Lime, 44 Charcoal
  • 50 Stokes - 29 Ash, 26 Lime, 47 Charcoal


100 Limestone, 100 Leeks, 100 Dried Flax, 100 Papyrus

  • 33 Stokes - 65 Ash, 23 Lime, 43 Charcoal
  • 40 Stokes - 70 Ash, 24 Lime, 45 Charcoal
  • 50 Stokes - 76 Ash, 26 Lime, 48 Charcoal
  • 60 Stokes - 80 Ash, 27 Lime, ? Charcoal

Speed?

How quickly does the color cycle? I tried once and apparently missed the stoking point entirely, even though I thought I was seeing the color progression. -- Shebi 00:10, 13 January 2009 (EST)

  • The speed will vary, in general the fire will remain in the stoke phase for around 14 seconds after you stoke. The next phase where the stoke button is removed and the fire will change colors seems to be around 5-10 seconds. The no stoke phase that follows is high variable, I have seen it last as little as 5 seconds and go for over 40. --Vulpine 18:08, 26 January 2009 (EST)
  • I used a count of 12 seconds before stoking going 1 and 2 and .... and this worked well for about 10 stokes until my husband walked in. I broke the rhythm but I was able to stoke again about 5 times and then it smouldered out. My yield was between the 10-15 stoke yields. --Dianess 22:34, 5 February 2009 (EST)

Possible yield formulae

Using these formulae, and assuming 1 stoke = 45 teppyseconds, I get very good agreement with the data on this page (in general, +/- 1 for 80% of the data, with a few obvious outliers that are probably measurement errors):

t = int( (burning duration in teppyseconds) / 30 )
charcoal = int( t^(1/3) * 11 )
lime from 100 limestone = int( t^(1/3) * 6 )
ash from 100 flax = int( t^(1/3) * 5 )
ash from 100 leeks = int( t^(1/3) * 2 )
ash from 100 papy = int( t^(1/2) * 5 )

i.e. yield is proportional to the cube root of duration for everything except papyrus, which is proportional to the square root. Duration includes the ignition and smouldering-out time (so t=12 for 0 stokes - 6 teppyminutes from ignition to completion).

I will go ahead and put this on the main page since it agrees well.

I have not tested less than full loads yet. However, speculation:

 lime = int( t^(1/3) * int(limestone/16) )
 ash = int( t^(1/3) * int(flax/20) )
 ash = int( t^(1/3) * int(leeks/40) )     (Not 50! See below)
 ash = int( t^(1/2) * int(papy/20) )

Testing results:

 200 wood + 15 limestone + 19 flax, no stoking -> 25 cc, NO ash, NO lime
 200 wood + 16 limestone + 20 flax, no stoking -> 24 cc, 2 ash, 2 lime
 200 wood + 49 leeks, no stoking -> 24 cc, 2 ash. (Hmmm)
 200 wood + 39 leeks, no stoking -> 25 cc, NO ash
 200 wood + 19 papy, no stoking -> 25 cc, NO ash
 200 wood + 20 papy, no stoking -> 25 cc, 3 ash

--Inkoaten 19:33, 9 March 2009 (EST)