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User:Tunnen/Mutagens

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Disclaimer : I've only started in Tale 4 and have no experiance with previous tales. I've done research by reading the current and previous tale's wikis and through some conversations with other players. This information may or may not be correct as some of it may not have been observered directly by myself or is based off assumptions.

Current Mutagens

ID# Mutagen Name Left min. % Left max. % Right min. % Right max. %
Saq 1 Mottled, Phosphorescent and Reticulated 11.12% 13.33% 27.50% 29.72%
Saq 2 Calico, Reticulated and Spotted L-% L+% R-% R+%
Saq 3 Hairy, Mottled and Striped 15.79% 21.05% 26.32% 31.57%
Saq 4 Mottled, Smelly and Spotted L-% L+% R-% R+%

Calculating the Target Genes

  • Gene = genome_length * percentage


For example: What genes would "Toxin of Hairy, Mottled and Striped" (Saq 3) affect in Ankhet Wheat: Macumba's?

  • Ankhet Wheat: Macumba's genome is KYGYROUGRYGUGRUYORRGK
    • It's genome length is 19 (You don't count the Ks)
  • Toxin of Hairy, Mottled and Striped has a Left min/max% of 15.79-21.05% and a Right min/max% of 26.32-31.57%
    • 19 * 0.1579 = 3 (3.0001 truncated)
    • 19 * 0.2105 = 3 (3.9995 truncated)
    • 19 * 0.2632 = 5 (5.0008 truncated)
    • 19 * 0.3157 = 5 (5.9983 truncated)
  • On the left splint, gene 3 would be affected
    • KYG*Y*ROUGRYGUGRUYORRGK
  • On the right splint, gene 5 would be affected
    • KYGYR*O*UGRYGUGRUYORRGK
  • So if you were to put Macumba in both splits and used Toxin of Hairy, Mottled and Striped. Gene 3 and 5 will swap and you would end up with. (Macumba added for refrence only)
    • Name#1 - KYGOROUGRYGUGRUYORRGK
    • Name#2 - KYGYRYUGRYGUGRUYORRGK
    • Macumba- KYGYROUGRYGUGRUYORRGK


Calculating the Percentage

  • Min Percentage = gene / genome_length (Rounded up)
  • Max Percentage = (gene + 1) / genome_length (Rounded down... see note)


For example: You want to find out the percentage that cover Gene #5 of Ankhet Wheat: Macumba

  • Ankhet Wheat: Macumba's genome is KYGYROUGRYGUGRUYORRGK
    • It's genome length is 19 (You don't count the Ks)
  • You need to figure out the min and max percentage.
    • Min: 5 / 19 = 26.32% (0.2631578 rounded up)
    • Max: 6 / 19 = 31.57% (0.3157894 rounded down)
      • Note: Due to rounding, there is a small possibility of an error if a percentage calculated is right at the edge of that range. Though it should be very rare. Also if on the max value you end up with a value that doesn't round down, you need to subtract 0.01%
        • Example of that is figuring out the range of gene 11 of 40. 12/40 = 30.00% so the value should be 29.99%. To proof 40 * 0.2999 = 11 (11.996 truncated) whereas 40 * 0.3000 = 12.
          • If this still is as clear as mud, send me a chat and I'll try to explain my reasoning more clearly and in depth =P