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Difference between revisions of "Aperio 003 Data"

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(Created page with "Back to User:Aperio Aperio #3 Initial Grapes = 8 (50 trials of Clear Solvent [4 genes]) (1) KYRY 11 (1) RYRY 111 (2) RYYR 111 111 111 1 (2) YYRY 111 111 111 11 (1) YRY...")
 
m
Line 13: Line 13:
 
  RYYRYY 1
 
  RYYRYY 1
 
  YRYRYY 1
 
  YRYRYY 1
 +
      YRY RYY
 +
          RYY RYY (a span of 9 genes)
 +
OR
 +
        RY YRY Y
 +
              YRY RYY (a span of 11 genes seems pretty improbable knowing there are 2 more AND we lost the prepended G)
 +
 +
ORIGINAL
 +
    K GYR YYR YYR YYR K (12)
 +
            Q  Q  Q
  
 
  (1) K YRY
 
  (1) K YRY
Line 25: Line 34:
 
  (2)          RYY R of (2)
 
  (2)          RYY R of (2)
 
  (1)            YY RK
 
  (1)            YY RK
     K YRY RYY RYY RK
+
     K YRY RYY RYY RK (10)
 +
            Q  Q
 +
 
 +
Alternatively,
 +
    K YRY RYY RYY RYY RK (13)
 +
            Q  Q  Q
 +
 
 +
10 is supported by the loss of the G, suggesting shortening.  What is not clear is how we get the second shortening.  Would more solvent tests be useful?
 +
 
 +
Getting the right endpoint would tell me I've got it right but not how many YRYYs there should be
 +
Getting the left endpoint would tell me I've got it right and leave us with the same mystery
 +
Everything else is a failure (e.g. RYRYYR is pretty much a given)
 +
 
 +
Going to do a low-tech Quality Check on vineyards to see how many Qs I should be looking for.

Revision as of 06:40, 20 July 2011

Back to User:Aperio

Aperio #3 Initial Grapes = 8 (50 trials of Clear Solvent [4 genes])
(1) KYRY	11
(1) RYRY	111
(2) RYYR	111 111 111 1
(2) YYRY	111 111 111 11
(1) YRYR	111 1
(3) YRYY	111 111 111 111 111 11
(1) YYRK	111
Aperio #3 Initial Grapes = 8 (2 trials of Crystal Solvent [6 genes])
RYYRYY	1
YRYRYY	1
      YRY RYY
          RYY RYY (a span of 9 genes)
OR
       RY YRY Y
              YRY RYY (a span of 11 genes seems pretty improbable knowing there are 2 more AND we lost the prepended G)
ORIGINAL
    K GYR YYR YYR YYR K (12)
           Q   Q   Q
(1) K YRY
(1)   YRY RYY
(1)   YRY R
(1)    RY RY
(1)     Y RYY (of 3)
(1)       RYY RYY
(1)       RYY R (of 2)
(1)        YY RY (of 2)
(2)         Y RYY (of 3)
(2)           RYY R of (2)
(1)            YY RK
    K YRY RYY RYY RK (10)
            Q   Q
Alternatively,
    K YRY RYY RYY RYY RK (13)
            Q   Q   Q

10 is supported by the loss of the G, suggesting shortening. What is not clear is how we get the second shortening. Would more solvent tests be useful?

Getting the right endpoint would tell me I've got it right but not how many YRYYs there should be Getting the left endpoint would tell me I've got it right and leave us with the same mystery Everything else is a failure (e.g. RYRYYR is pretty much a given)

Going to do a low-tech Quality Check on vineyards to see how many Qs I should be looking for.